Antimony is alloyed with lead to increase the rigidity of components used in the construction of lead storage batteries.
3.536 g of a particular metallic alloy, compounded of only Pb and Sb, can be quantitatively converted into a 4.110-g mixture of the oxides PbO2 and Sb2O4.
What was the percentage (by mass) of antimony in the alloy?
Can you please explain to me how to do this?
2006-10-14 18:55:50 · 1 answers · asked by Magnitudex 2 in Science & Mathematics ➔ Chemistry
M(Sb) = 121.760 = 122
M(Pb) = 207.2 = 207
M(O) = 15.9994 = 16
N moles of PB + M moles of SB = 3.536 g
207Pb + 122Sb = 3.536
N moles of PbO2 + M moles of SbO2 =4.110 g
(1M Sb --> M/2 of Sb2O4 = 1M of "SbO2")
(207+32)Pb + (122+32)Sb = 4.110
29158Sb = 845.104
31878Sb = 850.77
2720Sb = 5.66
Sb = 0.00208088
207Pb + 122(0.00208088) = 3.536
207Pb = 92.82% of 3.536
122Sb = 7.18%
2006-10-14 20:00:17 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋