a 100g ball on a 60cm long string is swung in a vertical circle about a point 200cm above the floor. The string suddenly breaks when it is parallel to the ground and the ball is moving upward. The ball reaches a height 600cm above the floor . what was the tension in the string the instant before it broke?
2006-10-14 18:16:09 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
first you have to find the initial velocity of the ball when the string breaks. Use the following equation for that - Vo^2=-2g(xf-xi)
Vo = 8.854 m/s
Now use the formula for circular motion - Ac = V^2/r
so Ac = 130.67 m/s^2
F = m*Ac = .1 kg * 130.67 m/s^2 = 13.067 N
The tension force is equal to this centripetal force = 13.067 N
2006-10-14 18:30:12 · answer #1 · answered by resurrection_of_t_o 2 · 0⤊ 0⤋
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2016-12-04 20:30:04 · answer #2 · answered by Anonymous · 0⤊ 0⤋
0 - v^2 = -2as = -2(980 cm/sec^2)(400 cm)
F = (mv^2)/r = 2(100 g)(980 cm/sec^2)(400 cm)/(60 cm)
F = 1306667 dynes = 13.067 N
2006-10-14 18:37:57 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
what is the elasticity of the string?
2006-10-14 18:17:51 · answer #4 · answered by Spadesboffin 3 · 0⤊ 1⤋
.4 NM
2006-10-14 18:27:35 · answer #5 · answered by BbA 2 · 0⤊ 0⤋