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A 70.0 kg person stands on a scale in an elevator. What is the apparent weight in each of the following situations?
(a) when the elevator is accelerating upward with an acceleration of 1.50 m/s2

(b) when the elevator is moving upward at a constant speed

(c) when the elevator is accelerating downward with an acceleration of 1.90 m/s2

2006-10-14 16:44:05 · 3 answers · asked by Alan l 1 in Education & Reference Homework Help

3 answers

The weight when elevator is still is 70*gN = 70*9.8N. When the car accelerates upward, the weight increases to 70*(9.8 + 1.5)N.

When the elevator moves at constant speed, there is no effect on the weight.

For downward acceleration, the elevator's acceleration subtracts from g, so the result is 70*(g-1.9)N

2006-10-14 21:39:11 · answer #1 · answered by gp4rts 7 · 0 0

(a) 70 x (9.8 + 1.5) / 9.8 = 80.7 kg
(b) 70 kg
(c) 70 x (9.8 - 1.9) / 9.8 = 56.4 kg

2006-10-15 00:02:40 · answer #2 · answered by naike_10021980 2 · 0 0

a

no b

no c

no, it's a




























DO YOUR OWN HOMEWORK.

2006-10-14 23:51:52 · answer #3 · answered by xcrimsonxphoenixofxhellx 3 · 1 0

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