5/2t-t=3+3/2t?

Question

i couldnt figure it out

Answer 1

Sorry,But your question is out of place,
According to it,
5/2t-t=3+3/2t (sic)
= 5/2t-3/2t-t=3 (sic)
= t-t=3 (sic)
or 0=3 (sic)
Not possible!

Answer 2

I'm assuming that's (5/2) * t - t = 3 + (3/2)*t. Is that correct?
If so, simply multiply & then subtract out your t coefficients to get:
(3/2) * t = 3 + (3/2) *t
(3/2)*t -(3/2)*t = 3. Unfortunately, this means that 3=0 which obviously isn't true.

However, if the equation reads 5/(2t) - t = 3 + 3/(2t) we get something different.
First, subtract 3/(2t) from both sides.
5/(2t) - 3/(2t) - t = 3 + 3/(2t) - 3/(2t)
2/(2t) - t = 3
The 2s cancel (1/t) - t = 3
Multiply through by t
1 - t^2 = 3t
Set the equation equal to zero, by moving everything to the right.
0 = t^2 + 3t - 1
Does that help? You might check my math.

Answer 3

5/2t-t=3+3/2t or,5/2t-t-3/2t=3 or,0t=3 or t=3/0 =undefined lThere is some mistake in the equation you have given.In mostprobability,it would be like this..... 5/2t-t=3-3/2t or,5/2t-t+3/2t =3 or,3t=3 or,t=3/3=1