It appears that 2 sides are the same. The longest side would be 43.
Use the cosine rule to determine the angle opposite this side
using
43*43= 543.25 + 543.25 -2 *Square root of (543.25)*Square root of (543.25) Cos X
the remaining andles are (180-X)/2 each
2006-10-14 16:05:16
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answer #1
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answered by Willy Brown 2
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This is an isoceles triangle. Therefore you can bisect it into two congruent right triangles. Each one has a hypotenuse of h=sqrt(543.25), and one leg of length a=43/2. The other leg has a
It follows that the angles opposite the two equal sides have equal measure, t, that satisfies
cos t = a/h
and the third angle, which I'll call u, can be obtained by subtracting the other two from 180, or using the formula
sin u/2 = a/h.
2006-10-14 15:44:20
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answer #2
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answered by James L 5
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you use sin/cos/tan
if an angle you want has the opposite and adjacent sides 4 and 5
you would use: tan A = opposite/adjacent
tan A = 4/5, then use a calculator to find tan^-1(4/5)
which gives A =38.66
sin A = opposite/hypotenuse
cos A = adjacent/hypotenuse
the hypotenuse is the longest side, the opposite is the one right in front of it, and the adjacent is the one right next to it.
See the source!
2006-10-14 15:41:47
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answer #3
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answered by icez 4
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the angles opposite the side square root of 543.25 are the same and can be solved by
inverse cos (43 / (square root of 2173))
The angle opposite the side 43 can be solved in 2 ways.
2 (inverse sin (43 / (square root of 2173)))
alternatively, use
180 - 2(inverse cos (43/(square root of 2173)))
2006-10-14 15:58:59
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answer #4
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answered by naike_10021980 2
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Use the law of cosines: C^2 = A^2 + B^2 - 2ABcos8 (8 = theta)
This will give 8 between the legs A&B when solved for cos8.
2006-10-14 15:50:27
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answer #5
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answered by Steve 7
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law of sines:
let A, B & C be the sides & a, b, & c be the oposite angles:
A/sin a=B/sin b=C/sin c
Given A, B & C, you have 3 unknowns, a, b & c; & 3 equations:
A/sin a=B/sin b
A/sin a=B/sin b
&
a+b+c=180 degrees
solve simultaneously.
In this example, it is a little simpler since 2 of the sides (& hence 2 of the angles) are equal so you only have 2 equations & 2 unknowns.
2006-10-14 15:47:11
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answer #6
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answered by yupchagee 7
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You need to use the formulas for Sine, Cosine and Tangent:
http://www.gcseguide.co.uk/sin,_cos,_tan.htm
or
http://www.ac.wwu.edu/~vawter/PhysicsNet/Topics/Vectors/MeaningOfSine.html
2006-10-14 15:38:32
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answer #7
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answered by Anonymous
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Ouch my brain hurts
2006-10-14 15:38:00
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answer #8
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answered by shelsi 3
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