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I need either a formula, answer, or explanation.

2006-10-14 15:37:10 · 8 answers · asked by Che Revis 1 in Science & Mathematics Mathematics

8 answers

It appears that 2 sides are the same. The longest side would be 43.
Use the cosine rule to determine the angle opposite this side
using

43*43= 543.25 + 543.25 -2 *Square root of (543.25)*Square root of (543.25) Cos X

the remaining andles are (180-X)/2 each

2006-10-14 16:05:16 · answer #1 · answered by Willy Brown 2 · 0 0

This is an isoceles triangle. Therefore you can bisect it into two congruent right triangles. Each one has a hypotenuse of h=sqrt(543.25), and one leg of length a=43/2. The other leg has a

It follows that the angles opposite the two equal sides have equal measure, t, that satisfies

cos t = a/h

and the third angle, which I'll call u, can be obtained by subtracting the other two from 180, or using the formula

sin u/2 = a/h.

2006-10-14 15:44:20 · answer #2 · answered by James L 5 · 0 0

you use sin/cos/tan

if an angle you want has the opposite and adjacent sides 4 and 5
you would use: tan A = opposite/adjacent

tan A = 4/5, then use a calculator to find tan^-1(4/5)
which gives A =38.66

sin A = opposite/hypotenuse
cos A = adjacent/hypotenuse

the hypotenuse is the longest side, the opposite is the one right in front of it, and the adjacent is the one right next to it.

See the source!

2006-10-14 15:41:47 · answer #3 · answered by icez 4 · 0 0

the angles opposite the side square root of 543.25 are the same and can be solved by

inverse cos (43 / (square root of 2173))

The angle opposite the side 43 can be solved in 2 ways.

2 (inverse sin (43 / (square root of 2173)))

alternatively, use
180 - 2(inverse cos (43/(square root of 2173)))

2006-10-14 15:58:59 · answer #4 · answered by naike_10021980 2 · 0 0

Use the law of cosines: C^2 = A^2 + B^2 - 2ABcos8 (8 = theta)

This will give 8 between the legs A&B when solved for cos8.

2006-10-14 15:50:27 · answer #5 · answered by Steve 7 · 0 0

law of sines:
let A, B & C be the sides & a, b, & c be the oposite angles:
A/sin a=B/sin b=C/sin c
Given A, B & C, you have 3 unknowns, a, b & c; & 3 equations:
A/sin a=B/sin b
A/sin a=B/sin b
&
a+b+c=180 degrees

solve simultaneously.
In this example, it is a little simpler since 2 of the sides (& hence 2 of the angles) are equal so you only have 2 equations & 2 unknowns.

2006-10-14 15:47:11 · answer #6 · answered by yupchagee 7 · 0 0

You need to use the formulas for Sine, Cosine and Tangent:
http://www.gcseguide.co.uk/sin,_cos,_tan.htm

or

http://www.ac.wwu.edu/~vawter/PhysicsNet/Topics/Vectors/MeaningOfSine.html

2006-10-14 15:38:32 · answer #7 · answered by Anonymous · 0 0

Ouch my brain hurts

2006-10-14 15:38:00 · answer #8 · answered by shelsi 3 · 0 0

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