help!!! factor 4x^2+x-6?

Answer 1

4x^2 +x - 6
4x^2 + 4x -3x -6
4x(x + 1) -3( x + 2)
(x+2) (4x -3 )
anwer x = -2 , 3/4

Answer 2

Auto...--You are way off in Wonderland. Since there are no factors of 24 that have a difference of 1, this does not have integer factors. You have to do it like the first to answerers did and use the quadratic formula to find the roots of the expression when set equal to zero.

Secondly, Auto... you can't possibly SOLVE this expression. It is not an equation. The question that was asked was, How do you factor this expression. x=some number is not a way to write factors.

Try multiplying the two factors you came up with and see if you get the original expression. You won't because your factoring is way off.

Answer 3

This doesn't have a nice factorization. You'll need to use the quadratic formula to find the solutions of 4x^2 + x - 6 = 0,

x = (-1 +/- sqrt(1 - 4(4)(-6)))/8
= (-1 +/- sqrt(97))/8

so your factorization is

(x - (-1 + sqrt(97))/8)(x - (-1 - sqrt(97))/8)

Answer 4

The factoring is not neat on this problem thus use the quadratic equation to solve for the solutions. Then you can plug them into the factoring representation.

Quadratic eqaution is [-b[+-]sqrt(b^2-4ac)]/2a, with a=4, b=1, c=-6 in this equation

Plugging in these values, you get [-1[+-]sqrt(1+96)]/8

Thus, your two solutions are [-1+sqrt(97)]/8 and [-1-sqrt(97)]/8

Plugging these solutions into the factoring representation, you get:

(x+[-1+sqrt(97)]/8)*
(x+[-1-sqrt(97)]/8)

Hope this helps