2006-10-14 14:15:45 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Or give me sites where I can find these?
2006-10-14 14:16:58 · update #1
Hi. Watch the moons of Jupiter.
2006-10-14 14:17:53 · answer #1 · answered by Cirric 7 · 0⤊ 0⤋
This is an experiment I performed myself:
Get a laser and a precision motor on which is mounted an 8-sided mirror (uniformly octagonal of course). The motor must either have a controller that can precisely adjust its speed, or you must set up another laser beam with a counter; in any case, you need to know how fast the mirror is turning.
Set up the laser and mirror, stationary, so the laser bounces off one mirror, bounces off another mirror across the room, and bounces off the adjacent mirror on the motor into a sensor. This is your baseline setup.
Turn on the motor. You will notice that the point of light moves away from the sensor in the direction of rotation. (Why is this?) As the motor speeds up, you will see a new point of light appearing from the other direction. Increase the speed until the new point of light is aligned with the sensor.
When this occurs, note the speed of rotation of the mirror. The time in question is 1/8 of that time; in that period the light could bounce off mirror 1, cross the room, bounce off another mirror, cross the room again and bounce off the SAME MIRROR IT BOUNCED OFF IN THE FIRST PLACE, and proceed into the detector.
We got a value within 5% or so of the accepted value of c.
2006-10-14 21:25:53 · answer #2 · answered by poorcocoboiboi 6 · 0⤊ 0⤋
this expeerime nt is a prototype. now take the time taken by the sun's rays to reach the equator as 8 minutes or 8*60 i.e., 480 seconds or approximate it to be 500secs. take the distance between the earth and sun as 1.5 x 10^11 m. divide this value with time you get it as 3 x 10^8 m/s... this answer is right by me. but experimentally the one answered by poor coco somethin about the laser experiment is right. even you can take the light year value and divide it with the no of seconds in a year.
to find in this way:
1 light year =9.3 x10^15
no of secs in year .
divide the light year value by the no of secs.
you get the answer.
& that was a
nice question .
2006-10-14 21:36:26 · answer #3 · answered by arawind 1 · 0⤊ 0⤋
If you'd settle for a little lower frequency emf you can get into a radar and compare the interval between an emitted pulse with the return pulse for a known distance target.
2006-10-15 10:39:05 · answer #4 · answered by Nomadd 7 · 0⤊ 0⤋
You can calculate the speed of light using marshmellows and a microwave.
http://www.physics.umd.edu/ripe/icpe/newsletters/n34/marshmal.htm
2006-10-14 22:24:59 · answer #5 · answered by Mike C 2 · 0⤊ 0⤋
look it up on Google Scholar
2006-10-14 21:17:52 · answer #6 · answered by sur2124 4 · 0⤊ 0⤋
you can't tell me what to do
2006-10-15 03:41:50 · answer #7 · answered by lorentztrans 2 · 0⤊ 0⤋