Solve and explain please?
2006-10-14 14:12:08 · 6 answers · asked by racheldawnsmith311 1 in Science & Mathematics ➔ Mathematics
Factor out an xy: xy(8x^2 - 2xy - y^2).
For 8x^2 - 2xy - y^2, look for a factorization of the form
(ax+y)(bx-y)
where ab=8 and b-a=-2. b=2, a=4 work, so you have
xy(4x+y)(2x-y).
2006-10-14 14:19:33 · answer #1 · answered by James L 5 · 0⤊ 0⤋
By inspection x is a factor in all the terms
So is y and NOT its higher powers
so xy is a common facto and when extacted
the expression can be writen as
xy( 8x^2-2xy-y^2)
Now concentrate on th terms within the brackets and with practice you should be able to factorize the contwnts as
(4x + y)(2x-y)
Hence the complete solution is
8x^3y - 2x^2y^2 - xy^3 = xy (4x + y)(2x-y)
2006-10-14 14:58:25 · answer #2 · answered by Willy Brown 2 · 0⤊ 0⤋
Factoring polynomials thoroughly: x^3y + 2x^2y^2 + xy^3 aspect out the excellent easy aspect (GCF) = xy xy(x^2 + 2xy +y^2) aspect a trinomial xy(y + x) (y +x) very last outcome: xy(y + x) (y + x)
2016-12-04 20:19:43 · answer #3 · answered by Anonymous · 0⤊ 0⤋
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2006-10-14 14:26:27 · answer #4 · answered by Anonymous · 0⤊ 0⤋
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2006-10-14 14:14:16 · answer #5 · answered by sur2124 4 · 0⤊ 0⤋
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2006-10-14 14:18:14 · answer #6 · answered by Anonymous · 0⤊ 0⤋