A block of mass 8.00 kg is pushed up against a wall by a force P that makes a 50.0° angle with the horizontal

Question

A block of mass 8.00 kg is pushed up against a wall by a force P that makes a 50.0° angle with the horizontal. The coefficient of static friction between the block and the wall is 0.267. What are the possible values for the magnitude of P that allow the block to remain stationary.

N (min)
N(max)

Answer 1

Assume P has a component up the wall
The Component up the wall is P sin 50

The Normal Reaction would be
P times cos(50)
The maximum friction force available is
0.267 times P times Cos(50)

If the Block is at the virge of sliding down the friction force would be upward.
For Equilibrium
0.267 times P times Cos(50) + P sin(50) = 8 times 9.81

If the Block is at the virge of sliding up the friction force would be downward

For Equilibrium
P sin(50) = 8 times 9.81 + 0.267 times P times Cos(50)

Answer 2

Pizza.

Answer 3

http://en.wikipedia.org/wiki/Coefficient_of_friction