E.O.F. of ice is 6.020.H.C. of liquid H2O is 75.4.what is the smallest number of ice cube at 0 degree........,

Question

(continuing) each containing one mole of water, necessary to cool 500g of liquid water initially at 20 degree to 0 degree?

E.O.F=ethalpy of fusion in the unit of kJ/mol
H.C=heat capacity in the unit of J/mol degree

the answer is 7..but i don't know it is derived..please show me a step by step solution.thank you

Answer 1

500g of liquid water = 27.78 moles of water.
27.78 * HC * 20degrees = 41.8889 KJ.
41.8889KJ / (6.020KJ/cube) = 6.96 cubes.