how do you solve
2/x+1/m=3/y for m
when i solved it i got m=xy but i think that is wrong
2006-10-14 07:54:06 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2/x + 1/m = 3/y
subtract 2/x from both sides
1/m = 3/y - 2/x
multiply both sides by m
1 = m (3/y - 2/x)
divide both sides by (3/y - 2/x) to get m on one side by itself
1/(3/y - 2/x) = m
that can be further reduced to
m = y/3 - x/2
2006-10-14 08:07:54 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Multiply all terms by mxy
2my + xy = 3mx
Group m on one side of the equation
2my - 3mx = -xy
factor out m
m(2y -3x) = -xy
divide by (2y - 3x)
m = -xy /(2y - 3x)
2006-10-14 09:02:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2/x+1/m=3/y
Subtract 2/x:
1/m=3/y-2/x
Multiply by m/(3/y-2/x):
1/(3/y-2/x)=m
And the problem is thus solved. If you want to simplify further:
m = 1/(3/y-2/x) = 1/(3x/(xy)-2y/(xy)) = xy/(3x-2y)
2006-10-14 08:02:03 · answer #3 · answered by Pascal 7 · 0⤊ 1⤋
1st: examine your calculator instruction manual 2d: assume you have y1 = p(x) in the graphing mode, in many cases now you enter the kind for the x & y values, [0,10] thus for x and [-20,20] for y, then touch the graph button, zoom in on the basis....yet examine the instruction manual
2016-10-16 04:49:27 · answer #4 · answered by gaffke 4 · 0⤊ 0⤋
Get m on one side
2006-10-14 07:56:22 · answer #5 · answered by Anonymous · 0⤊ 1⤋