ugg! Help. If I were given: f(x) = e^2x, g(x) = sin 2x, and h(x) = 2x^2. Let p(x) = g[f(x)]. Then p'(x) =?

Question

having trouble with this problem

Answer 1

the answer after differentiating p(x) is

4*(e^2x)*cos(2e^2x)........

Answer 2

Take it one step at a time:

g[f(x)] = sin 2(f(x))

= sin 2e^2x

so now take the derivative of sin 2e^2x to get p'(x) {since p(x) = sin 2e^2x

HTH!