2006-10-14 05:26:42 · 5 answers · asked by chris 2 in Science & Mathematics ➔ Mathematics
Maybe.What's your take on it?
2006-10-14 05:27:52 · answer #1 · answered by Anonymous · 0⤊ 0⤋
g'(x) = (x-5)^2 + 2(x+2)(x-5) = (x-5)[(x-5)+2(x+2)]
= (x-5)(3x-1).
g''(x) = (3x-1) + 3(x-5) = 6x - 16 = 2(3x-8), so yes, it does have an inflection point when x=8/3.
2006-10-14 12:32:28 · answer #2 · answered by James L 5 · 0⤊ 0⤋
this is a function.
so plug 8/3 in for x.
ur equation will look like this:
g(8/3)=(8/3+2)(8/3-5)^2
so solve!!!!!!
(i think)
2006-10-14 12:37:09 · answer #3 · answered by maiabell2 2 · 0⤊ 0⤋
g(x)=(x+2)(x+5)^2
dy/dx=3(x^2+8x+15)
dy/dx=0
so,
x^2+8x+15=0
x=-3,-5(pt of inflexion)
x=8/3 is not a pt of inflexion
2006-10-14 12:38:42 · answer #4 · answered by hi 2 · 0⤊ 0⤋
I would say yes !
2006-10-14 12:32:08 · answer #5 · answered by shamu 2 · 0⤊ 0⤋