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f(x) has a local minimum at (0, 0) and a local minimum at (-1, 1)
f(x) has a local minimum at (0, 0) and a local maximum at (-1, 1)
f(x) has a local minimum at (0, 0) and a local maximum at (1, 1)
f(x) has a local maximum at (0, 0) and a local maximum at (-1, 1)
or none of the above is true
2006-10-14 05:22:47 · 2 answers · asked by Doug 2 in Science & Mathematics ➔ Mathematics
f'(x) = 6x + 6x^2 = 6x(1 + x), so f'(x) = 0 at x=0,-1
f''(x) = 6 + 12x. f''(0) = 6 and f''(-1) = -6.
So, f has a local minimum at (0,0) and a local maximum at (-1,1)
2006-10-14 05:26:22 · answer #1 · answered by James L 5 · 0⤊ 0⤋
Any or all could be true.What's your take on it?
2006-10-14 12:25:37 · answer #2 · answered by Anonymous · 0⤊ 0⤋