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A cue stick hits a cue ball with an average force of 23 N for a duration of 0.024 s. If the mass of the ball is 0.17 kg, how fast is it moving after being struck?

2006-10-14 04:51:18 · 1 answers · asked by nt 2 in Science & Mathematics Physics

1 answers

An impulse is defined as a change in momentum, and can be found my multiplying an applied force by its duration. In this case, that's 23 * 0.024 = .552 kg-m/s. Momentum is also mass times velocity, and your velocity is unknown. so 0.17v = 0.552 ==> v = 3.25 m/s.

2006-10-14 04:54:45 · answer #1 · answered by DavidK93 7 · 0 0

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