What is the type of hybridisation for...?

Question

The type of hybridisation and the shape of molecule for
IO3^-? (3 molecules of oxygen..and with the negative sign)

Answer 1

first, you have to count the electrons
3*6 (O) + 1*7(I) + 1= 26e-
However, all elements involved require an octet= 4*8 = 32e-
32e- - 26e- = 6e- → (6e-)/2 = 3, that means you need 3 simple bonds, and therefore, the central atom (I), will have one single pair of electrons plus the 3 bonds.
I: [Kr] 4d10///-5s2-5p5, because it only has one space in one of the p orbitals to bond, it must promote electrons to 5d
When you are done you get:
4d10-5s2-5p3-5d2, you take 5s orbital (this is the lone pair) and all 3 5p orbitals (each semi filled, so it can bond with the 3 O), and hybridize all 4 orbitals into 5sp3.
In consequence, the shape of the molecule is trigonal pyramidal, with bonding angles of 107º (the lone pair makes them smaller from the usual 109,5º)

Answer 2

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Answer 3

Trigonal Pyramidal.
sp2 hybrid

Answer 4

iodine has the excess electron and completes its octet four electron pairs in tetrhedral shape and three oxygen has co ordinate bonds with three pairs so the shape of the molecule is pyramidal

Answer 5

sp3d2. Five bonds to O are needed.
The shape should be trigonal planar.

Answer 6

iodate is trigonal

Answer 7

yup your right hee