2006-10-13 20:56:36 · 6 answers · asked by Demon 1 in Science & Mathematics ➔ Chemistry
go to
http://chemistryonline.ifastnet.com/periodic_table.htm
it has a periodic table that lists the boiling point, melting point, atomic mass, atomic number, the discoverer, etc of each and every element.
2006-10-14 05:21:10 · answer #1 · answered by shadab_ansari2005 3 · 0⤊ 0⤋
Vanadium has multiple oxidation states the most prevalent is V^5+ and the second most prevalent is V^2+. If you look at the shorthand electron configuration for V it is [Ar] 3d3 4s2 if you look at the highest energy level for Vanadium some consider it as n = 4 which would have 2 valence electrons. However, you can consider the 3d contributing to the valence electrons as well so then instead of 2 valence electrons it really has 5 from the 3d3 and 4s2.
2016-03-17 04:43:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋
If you're talkin about the Vanadium in the periodic table (the average atomic mass-51), then the
# of neutrons:28
# of electrons:23
2006-10-14 04:10:51 · answer #3 · answered by Daisy 2 · 0⤊ 1⤋
Numbers of electrons = number of protons = 23,
Numbers of neutrons = 27
2006-10-14 06:04:26 · answer #4 · answered by MANSI R 2 · 0⤊ 0⤋
I am assuming you are talking about Vanadium 51.
It has 23 protons, 23 electrons and 28 neutrons.
If you want to impress your teacher next time, ask about what isotope is he referring to? Obviously, learn about isotopes if you do not know the subject.
2006-10-14 02:23:08 · answer #5 · answered by Dr. J. 6 · 0⤊ 1⤋
Numbers of electrons = number of protons = 23,
Numbers of neutrons = 27
2006-10-13 21:11:45 · answer #6 · answered by Andreja K 3 · 0⤊ 2⤋