2006-10-13 19:52:28 · 5 answers · asked by vmohini 1 in Science & Mathematics ➔ Mathematics
assuming 1/3-^2 means 1/3^-2,
a^2 + b^2 = 81 + 1/81 = 81.012345679
2006-10-13 20:01:10 · answer #1 · answered by Helmut 7 · 1⤊ 0⤋
a=1/3-^2
a=3^2
a= 9.
a= b-1/3+^2
sqrt a=b-1/3
sqrt 9= b-1/3, 3=b-1/3, b-1=9, b= 10
a=9, b=10
a(square)+b(square)= 9(suare)+10(square)= 81+100= 181
there fore answer is 181
2006-10-13 22:24:56 · answer #2 · answered by amar s 1 · 0⤊ 0⤋
a=1/3-^2 I think you mean 1/3^-2
a^2=(3^2)^2=3^4=81
b-1/3+^2 I think you mean b=1/3^2
b^2=(1/3^2)^2=1/81
a^2+b^2=81 1/81
2006-10-17 09:47:24 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
you mean a = (-1/3)^2 & b = (1/3)^2
a^2 + b^2 = 2 / 9 = 0.2222
2006-10-13 20:31:11 · answer #4 · answered by nayanmange 4 · 0⤊ 0⤋
assume a=1/3^-2,b=1/3^2
a^2+b^2=[1/3^-2]^2+[1/3^2]^2
=[3^2]^2+[1/9]^2
=81+1/81
=81+.0123
=81.0123
2006-10-13 22:12:44 · answer #5 · answered by openpsychy 6 · 0⤊ 0⤋