Consecutive odd integers are 2 apart, like 5 and 7. So set up your numbers this way:
Small:x
middle: x+ 2
Large: x+ 4
Your sentence gives you the equation
3(x+4) = 7x
3x + 12 = 7x
12 = 4x
x = 3
x+2 = 5
x+4 = 7
2006-10-13 16:19:46
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answer #1
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answered by PatsyBee 4
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3, 5, 7
2006-10-13 16:15:18
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answer #2
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answered by spongeworthy_us 6
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3, 5, 7
2006-10-13 16:09:14
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answer #3
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answered by Grundoon 7
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x, x + 2, x + 4
3(x + 4) = 7x
3x + 12 = 7x
-4x = -12
x = 3
The numbers are 3, 5, and 7
2006-10-13 16:17:15
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answer #4
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answered by Sherman81 6
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the integers are:
3,5,7
Thats because 7*3=21 &
3*7=21
Thats exactly what you asked.
Hope it helps.
2006-10-13 16:16:48
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answer #5
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answered by Anurag S 2
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3 consecutive odd integers can be written as
(m, m+2, m+4) and (m)mod(2)=1
we want that
7m=3(m+4) & (m)mod(2)=1<=>
7m=3m+12 & (m)mod(2)=1<=>
4m=12........& (m)mod(2)=1<=>
m=3............& (m)mod(2)=1 (true) =>
(m, m+2, m+4)=(3,5,7)
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2006-10-13 16:26:50
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answer #6
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answered by Broden 4
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2n+1, 2n+3, 2n+5,
3(2n+5) = 7 (2n+1)
6n-14n=7-15
-8n=-8
so n=1
so the integers are 3,5,7
2006-10-13 16:13:27
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answer #7
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answered by Anonymous
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