2006-10-13 15:32:30 · 11 answers · asked by Deidrebm 1 in Science & Mathematics ➔ Mathematics
(7p + 6q)^2
(7p + 6q)(7p + 6q)
49p^2 + 84pq + 36q^2
QED
2006-10-13 15:58:17 · answer #1 · answered by CSUFGrad2006 5 · 0⤊ 0⤋
Use FOIL
(7p + 6q)(7p + 6q)
49p^2+42pq+42pq+36q^2
49p^2+84pq+36q^2
2006-10-16 20:22:42 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
(7p+6q)^2= (7p+6q)(7p+6q)= 49q^2+84pq+36q^2. REAL funny that every one started changing there answers after someone gave the right answer. Cuz when I started typing my answer there was only one right answer there.
2006-10-13 23:08:55 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(7p + 6q)^2
(7p + 6q)(7p + 6q)
49p^2 + 42pq + 42pq + 36q^2
49p^2 + 84pq + 36q^2
2006-10-13 23:10:31 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
(7p+6q)^2
we know the rule is(a+b)^2=a2+2ab+b2
now(7p+6q)^2
=(7p)^2+2*7p*6q+(6q)^2
=49p^2+84pq+36q^2
2006-10-13 22:48:33 · answer #5 · answered by Ahsan T 2 · 1⤊ 0⤋
This is a sample of special products.... squaring a binomial... The first step is to square the first term, then, Multiply the first and the second term and multiply the product by 2. and lastly, square the last term... So, the answer is... (49p^2+84pq+36q^2)
2006-10-14 08:32:26 · answer #6 · answered by Steph_kinse 2 · 0⤊ 0⤋
umm... that can be re-writeen as (7p + 6q)(7p + 6q)... which is...
49p^2 + 84pq + 36q^2
2006-10-13 22:36:36 · answer #7 · answered by futurefbiguy 2 · 2⤊ 0⤋
(7p+6q)(7p+6q)
49p^2+36q^2+84pq
2006-10-13 22:37:00 · answer #8 · answered by aznfobboytly 3 · 2⤊ 0⤋
49p^2 + 26pq + 36q^2
2006-10-13 22:34:16 · answer #9 · answered by fcas80 7 · 0⤊ 1⤋
(a+b)^2 os a^2+2ab+b^2
using this property:
49p^2+84pq+36q^2
2006-10-13 23:00:34 · answer #10 · answered by wakoko 2 · 0⤊ 0⤋