I need to write the net ionic reaction for the neutralization of HF(aq) by NaOH(aq).?

Question

HELP!

The answer below is not correct according to the quiz I'm taking. Anyone else?

Answer 1

The over-all balanced equation is:

HF (aq) + NaOH (aq) --> NaF (aq) + H2O (l)

But the net ionic equation is:

H+ + OH- --> H2O (l)

if one uses hydronium ions instead of protons:

H3O+ + OH- --> 2 H2O (l)

Answer 2

The total ionic equation is:

H+ + F- + Na+ + OH- --> H2O + Na+ + F -

Na+ and F- are spectator ions (appear in reactant and product) so-

The NET IONIC reaction is what actually happens:

H+ + OH- ---> H2O

Hope this helps.

Answer 3

Look, just write out the balanced chemical equation, and then separate each of the compounds into its ions, adding the appropriate + or - charge to them.

or

H+ + F- + Na+ + OH- gives

Na+ + F- + H+ + OH-

where "+" mean a +1 charge, and "-" means a -1 charge; notice that each ion on each side is the same (they cancel each other out. (You see, you can view H2O as splitting into H+ and OH- ions. H20 = HOH = H+ + OH-


And if that doesn't match the "quiz" your taking, then the quiz is wrong.

Answer 4

HF + NaOH ----> NaF + H2O

Trust me man. This is what you need.

Your additional details remind me of the beginning of Bab5, man. The Mimbari says to Sinclair: They are lying to you, they are lying to you....there is a hole in your mind..

Answer 5

HF(aq)+NaOH(aq) - NaF(aq) + H2O(l)