A stockroom worker pushes a box with mass 11.4 kg on a horizontal surface with a constant speed of 3.90 m/s. The coefIficient of kinetic friction between the box and the surface is 0.200 .
What horizontal force must be applied by the worker to maintain the motion?
Take the free fall acceleration to be g = 9.80 m/s^2.
If the force calculated in part (A) is removed, how far does the box slide before coming to rest?
Take the free fall acceleration to be g = 9.80 m/s^2.
2006-10-13 14:03:02 · 1 answers · asked by darkangelwattitude 1 in Science & Mathematics ➔ Physics
the applied force must be greater than the frictional force
therefore F(applied)> 0.200 x 11.4 x 9.8 = 22.344 Newtons.
if the force is removed then frictional force will come into play and exceed the applied force since applied force is 0, therefore the box comes to rest without traveling.
2006-10-13 14:13:52 · answer #1 · answered by Mysterious 3 · 0⤊ 0⤋