2006-10-13 13:48:24 · 20 answers · asked by j a 1 in Science & Mathematics ➔ Mathematics
First solve for x in the first equation:
2x+3=9
1) subtract 3 from both sides -----------> 2x=6
2) Divide by 2 on both sides -------------> x=6/2
therefore x = 3
Now plug in x = 3 to the expression 2x-3 to get its value
When x = 3, 4x-3 ----------> 4(3)-3 =9
Hope this helps
2006-10-13 13:50:27 · answer #1 · answered by JSAM 5 · 0⤊ 0⤋
Step1) We need to find the value of "x" first.
2x + 3 = 9
=> 2x = 9 - 3 ( since, we are shifting 3 to other side)
=> 2x = 6
=> x = 6/2
=> x = 3
We got the value of x = 3.
Step 2) Now we need to place the value of "x" in 4x - 3
which becomes as 4(3) - 3 [ here we are multilying 4 with 3 as the value of x is 3 from the result of Step 1.
Therefore, 4x - 3 = 4(3) - 3 = 12 - 3
= 9
2006-10-13 14:06:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
First we need to solve or find the value of x.
2x+3=9 (Subtract 3 from both sides)
2x=6 (Divide both sides by 2)
x=3
After getting the value of x, substitute the value of x to the next problem.
4x-3 Substitute 3 in place of x.
=4(3)-3
=12-3
=9
The value of 4x-3 is 9.
2006-10-13 15:23:46 · answer #3 · answered by lois lane 3 · 0⤊ 0⤋
2x + 3 = 9
2x = 9 - 3
2x = 6
x = 6/2 = 3
Now substitute the value of x = 3 in 4x - 3 = 4*3 - 3 = 9
2006-10-13 13:51:18 · answer #4 · answered by aazib_1 3 · 1⤊ 0⤋
If 2x + 3 = 9, then (multiply by 2)
4x + 6 = 18, so (subtracting 9)
4x -3 = 9
2006-10-13 14:00:20 · answer #5 · answered by Philo 7 · 0⤊ 0⤋
The answer is nine. the thing is, whatever you do to one side you must do to the other. the goal here is to have x by itself, so first, you subtract 3 from 2x + 3, and 9.
(2x + 3) - 3 is 2x.
9 - 3 is 6.
now you have 2x = 6. to get x by itself, you divide 2x by 2, and 6 by 2. 2x divided by 2 is x, and 6 divided by 2 is 3. you get x = 3. now you plug in 3 for x in the other equation. so 4x - 3 is actually (4 * 3) - 3. so you multiply 4 * 3 and get 12. so the it becomes 12 -3, which of course equals 9. hope that helps.
2006-10-13 13:56:55 · answer #6 · answered by Marisol H 2 · 0⤊ 0⤋
9
2006-10-13 13:51:16 · answer #7 · answered by gabe_moreland 1 · 0⤊ 0⤋
2x+3=9. Factor out the 3 by subtracting from both sides equals 2x=6. Factor out the 2 by division. x=3. so if x=3 in both equations then (4*3)-3=9. 12-3=9
2006-10-13 16:26:51 · answer #8 · answered by Anonymous · 0⤊ 0⤋
First, some the first one for x
2 x + 3 = 9
Subtract 3 from both sides
2 x = 6
Divide by 2
x = 3
Substitue
4x - 3
4(3)-3
12-3
9
So 4x - 3 = 9
2006-10-13 14:20:35 · answer #9 · answered by Anonymous · 0⤊ 0⤋
2x + 3 = 9
- 3 -3
2x = 6
/2x /2x
x =3
4(3) - 3 = 12 -3 = 9
So the answer is nine!!
You have to determine X and then fill it in on the other problem!
2006-10-13 15:21:39 · answer #10 · answered by Vennessa 2 · 0⤊ 0⤋