chem help?

Question

A mixture of Ne and Ar gases at 351 K contains twice as many moles of Ne as of Ar and has a total mass of 47.0 g. If the density of the mixture is 4.17 g/L, what is the partial pressure (in atm) of Ne?

Answer 1

In order to find the partial pressures of the gasses one must first find the total pressure of the mixture.
To do this we use the ideal gas law,
PV = nRT

You are told the temperature of the mixture explicitly.

You are told the number of grams of the mixtures as well as its density. Using these two pieces of information one can find the volume of the mixture and also the number of moles of the mixture.
The volume can be found by dividing the mass of the mixture by the given density.
To find the number of moles present in the mixture find the average molar mass of the gas. You are told that the mixture is 1/3 Ar and 2/3 Ne (twice as many moles of Ne as Ar). Add 1/3 the molar mass of Argon gas to the 2/3 of the molar mass of Neon gas from the periodic table...this is the average molar mass of the gas in the mixture. Divide the total mass of the mixture by the average molar mass of the gas to get the number of moles of gas.

You now have all the information you need to find the total pressure of the mixture.
You know the Volume (V), the number of moles (n), the temperature (T), and the gas rate constant (R) which is assumed knowledge.
Just plug into the ideal gas law,
PV = nRT
and solve for P,
P = nRT / V

One you have the total pressure...to find the partial pressure of one of the gasses, multiply the total pressure by the percentage of the gas in the mixture.
For example, Neon gas makes up 2/3 of the mixture or about 66.67%....multiply this percentage by the total pressure to find the partial pressure of Ne.
The same could be done for Argon by multiplying the total pressure by 1/3.

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Answer 2

a million.0 Potassium is somewhat electropositive aspect with low ionization skill. This sources makes the outer valance electrons ejection really basic with electric powered voltage. As you comprehend electric powered impulses are by using bypass of electrons 2.0 4 moles of Al reacts with 3 moles O2 giving Aluminum oxide. this signifies that 8 moles of Al want six moles of O2 3.0 team III era iv, probable the aspect is Ga and the Oxide is Ga2O3 4.0 1s2 2s2 2p6 3s13Px1