Calculate:?

Question

How many grams of solid AgNO3 will be needed to prepare 200 mL of 0.200 M solution?

How many grams of vitamin C (C6H8O6) would be contained in 25.0 Ml of 1.00 M solution?


How many moles of HCI is contained in 250 mL of 6.0 M solution?

Answer 1

1)

First you need to determine the number of moles of AgNO3 to determine the # of grams in the solution. Use the following:

Molarity = #moles/Volume (in Liters). We know molarity and volume, now solve for # moles.

# moles = Molarity*Volume = (0.2 mol/L)*(0.2 L) = 0.04 mol

Now, determine atomic weight of AgNO3 to determine # grams present in the solution.

1 Ag = 1(107.87)
1 N = 1(14)
3 O = 3(16)

Summing these, you get atomic weight = 169.87 g/mol

Thus # grams in original solution = (169.87 g/mol)*(0.04 mol) = 6.8 grams

2)

Use the same procedure:

# mol = (1 mol/L)*(0.025L) = 0.025 mol

Atomic Weight = 6(12.01)+8(1.008)+6(16) = 176.124 g/mol

Thus, # grams = (176.124 g/mol)*(0.025 mol) = 4.4 grams

3)

# mol = (6.0 mol/L)*(0.25 L) = 1.5 mol

Atomic weight = 1(1.008)+1(35.453) = 36.461 g/mol

# grams = (36.461 g/mol)*(1.5 mol) = 54.7 grams

------------------

In order to make sure your answers are correct, make sure the units are consistent

Hope this helps

Answer 2

try