Enthalpy is kickin my trash?

Question

A volume of 50.0 mL of 0.400 M HBr at 24.35°C is added to 50.0 mL of 0.400 M NaOH, also at 24.35°C. The final temperature is 27.06°C. Calculate the enthalpy change, H, in kJ for the following reaction:
HBr(aq) + NaOH(aq) --> NaBr(aq) + H2O(l)
(Heat capacity of the system is 0.418 kJ/?C.)

Answer 1

Calculate the quantities of HBr and of NaOH in moles:

n = C*V = 0.4*0.05 = 0.02 mol of HBr and 0.02 mol of NaOH (no one is in excess, both react fully)

Calculate the heat Q:

Q = K*ΔT = 0.418*(27.06 - 24.35) = 1.133 kJ

When 0.02 mol of HBr react we get 1.133 kJ of heat, so when 1 mol react we get:

q = 1.133/.o2 = 56.6 kJ

Then the enthalpy change is -56.6 kJ/mol

Answer 2

Enthalpy is magic,
Enthalpy is good,
Enthalpy kicked my @ss too,
Until I understood.

Enthalpy is transfer,
Enthalpy is heat,
You must study hard in school,
Or live on the street!!!!!!!!!!

Enthalpy is wonder,
Science at it's best...
Use your bunsen burner,
Put it to the test!!!!

Enthalpy is anger,
Science gone astray,
Hang out with my loser friends,
Drugs are bad, M'kay...

I wrote you a little song...I used to know all that crap, but I can't remember. Good luck!!! Don't take drugs, stay in school, and never, EVER eat fruitcake during the holidays (just 'cause it's NASTY!!!)