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A finishes the work in 10 days & B in 8 days individually. If A works for only 6 days then how many days should B work to complete A's work?

2006-10-13 06:33:27 · 3 answers · asked by yamuna s 1 in Science & Mathematics Mathematics

3 answers

First, you need to define some variables and parameters to make the math of this problem simpler.

First, let's define the total work as 'units'.

Let's defined the total work equal to 80 units (i chose this number to make the rates simple for A & B)

If A took 10 days to finish the total work, that means he worked at a rate of 8 units/day. Using the same logic, that means B worked at a rate of 10 units/day

Thus, if A worked for 6 days, that means he completed:

(8 units/day)*(6 days) = 48 units of total work.

That means, 80-48 = 32 units of work left to do.

Thus, the remaining amout of time that B has to use to complete A's work is:

remaining time = (32 units)/(10 units/day) = 3.2 days

Hope this helps

2006-10-13 06:48:38 · answer #1 · answered by JSAM 5 · 0 0

If A works 6 days, this would be 60% of the work. So there would only be 40% left for B to do.

So......B would need to work 3.2 days to complete the work. IE 8/.4=3.2

8 days to do 100% of the work divided by 40% of the work left to do

2006-10-13 13:38:54 · answer #2 · answered by phseamstress 2 · 1 0

40% of the job is left, and that will take B, .4*8 = 3.2 days to do.

2006-10-13 13:56:51 · answer #3 · answered by ag_iitkgp 7 · 0 0

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