lost on a word problem?

Question

You are selling tickets for a high school basketball game. Student tickets cost $3 and general admission cost $5. You sell 350 tickets and collect $1450. How many Student tickets did you sell?

Also how amny General admission tickets did you sell?

Answer 1

# of students = x
# of general public = y

3x+5y=1450-------------------------------------------------eqn #1

x+y=350------------------------------------------------------eqn #2

Multiplying eqn #2 by 3 we get
3x + 3y = 1050----------------------------------------------eqn #3

eqn #1 - eqn #3
2y=400
y=200

substituting value of y in eqn #2
x+200=350
Therefore x = 150

# of student tickets = 150, # of general tickets = 200.

Answer 2

As of right now you have two responses (which could be correct, I didn't bother to check), but more importantly those responses have no explanation whatsoever.

So, I will provide you with the explanation, and you can dish out points however, it doesn't matter to me in the least.

First:

If you buy, say $60.00 worth of perfume, and each one costs $20.00 each, how many did you buy?

3 right? Because 3*$20.00 is the total ---- $60.00

Same idea here exactly. You have tickets for two groups --- students -and- general admission.

Let's label the # student tickets as "s", and the # of general admission tickets as "g" so it's easy to with with, ok?

So, if the student tickets cost $3.00, and the general ad. cost $5.00 what can you say about how much money you got for the total sale?

It means that you can sell a total of "3s" student tickets, and "5g" general ad tickets. In math terms this is:

3s + 5g = total amount of money made from sale, which is $1450.

Make sense so far?

The problem tells you how many (total) were sold...(350). In math terms this is:

s + g = total # tickets sold, which is 350


You have two equations and two unknowns....all is right with the world now. Just solve ONE of these equations (doesn't matter which one) and substitute it into the other equation. Pick the easiest one.

Your two equations are:

s + g = 350
3s + 5g = 1450

==> s = 1450 - g

Substitute this into the other eq'n.

3(350 - g) + 5g = 1450

==> 3*350 - 3g + 5g = 1450
==> 3*350 + 2g = 1450
==> 2g = 1450 - 3*350
==> g = (1450 - 3*350)/2

Do this arithmetic and it will tell you how many general admission tickets were sold. THEN substitute THAT result into the equation above (s + g = 350) to get the number of student tickets sold.

Hope this helps you. Knowing HOW to go about these just takes practice and a little common sense is good too.

:)

Answer 3

They give you enough information to make two formulas in this problem, so you can have 2 variables (x=student tickets and y=general admission tickets).
Student tickets are 3 dollars and general admission are 5 and you sold a total of 1450 dollars in tickets. Thus, your first equation can be:

3x+5y=1450

you sold a total of 350 tickets, so the total of student tickets and general admission tickets will be 350, so your equation is:

x+y=350

To solve for the two equation you can use substitution. Solve on of the equations above to get one of the variables by itself on one side:

x+y=350

x=350-y

Substitute the value of x that you got above (in this case 350-y) into the second equation and solve for the second variable:

3(350-y)+5y=1450

1050-3y+5y=1450

2y=400

y=200

Then plug the value for y back into one of the original equations and solve for x:

x=150

Hope this helps.

Answer 4

let x be the amount of student tickets sold
350-x=amount of general admission tickets sold

(350-x)*5+3x=1450

Solve that equation and voola! :)

Answer 5

3s+5g=1450
s+g=350

200 general tickets (1000$) and 150 student tickets (450$)

Answer 6

3x+5y=1450
x+y=350
3x+3y=1050
2y=400
y=200
x=150
so 150 students tickets and 200 general tickets

Answer 7

3x + 5y = 1450
x+ y = 350

y = 350 - x, substitue into equation 1 and solve.

Answer 8

3x+5y=1450
x+y=350

Solve for x and y

Answer 9

As I said..........