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(y^3)(y^3)(y^3)/x^5 x (x^3)(x^3)/y^2...now where do I go from here to simplify? (x in the middle means multiply)

Thanks to you for helping me with other problems.

2006-10-13 05:41:43 · 7 answers · asked by bobbysgirlmeri 2 in Science & Mathematics Mathematics

7 answers

[y^9/x^5][x^6/y^2]
xy^7

2006-10-13 05:45:56 · answer #1 · answered by raj 7 · 1 0

Let me write it this way to make it clearer. I'll use * to mean multiply, so it isn't confused with an x term:

(y^3)(y^3)(y^3) ... (x^3)(x^3)
------------------ * -------------
.........x^5 ................y^2

When you multipy the same base, you can add the exponents.
So (y^3)(y^3)(y^3) becomes y^(3+3+3) or y^9. Do the same for (x^3)(x^3) to make it x^6

y^9 ... x^6
----- * -----
x^5 ....y^2

Now it should be simple to finish. To multiply fractions, multiply the numerators and multiply the denominators, to get a single fraction.
x^6 * y^9
-----------
x^5 * y^2

You can cancel out x^5 from x^6 to get x^1 (or x). You can cancel out x^2 from x^9 to get x^7. (When you divide, you subtract the exponents).

That leaves you with your final answer of:
x * y^7

2006-10-13 12:46:12 · answer #2 · answered by Puzzling 7 · 1 0

You could simplify using the law of indices.
y^3y^3y^3/x^5*x^3x^3/y^2
=y^9/x^5*x^8/y^2
=y^7*x^3
=x^3*y^7

2006-10-13 12:57:10 · answer #3 · answered by openpsychy 6 · 0 0

since you are multiplying, you can add the exponents:

(y^3)(y^3)(y^3)/x^5 simplifies to y^9/x^5
(x^3)(x^3)/y^2 simplifies to x^6/y^2

Multiplying these together, you get [y^9x^6]/[x^5y^2]

Dividing exponents means you subtract the power, thus you get:

y^(9-2)x^(6-5) which simplifies to y^7x^1

Hope this helps

2006-10-13 12:45:47 · answer #4 · answered by JSAM 5 · 0 0

(y^9/x^5 ) (x^6/y^2)
=(y^7)x

2006-10-13 12:49:27 · answer #5 · answered by locuaz 7 · 0 0

you have got to add all the power of the y together n all the power of the x together. In multiplication of x to the power of three and x to the power of three. THe formula is to add the power of the same entity x together. Pls refer to your mathematics textbook to reinforce the formula:)

2006-10-13 12:47:52 · answer #6 · answered by GOd is good all the time 1 · 0 0

XY^7

2006-10-13 12:51:46 · answer #7 · answered by Trans Atlantic 2 · 0 0

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