Let A be the number of days to complete the job working alone.
Let B be the number of days to complete the job working alone.
Each day A, does 1/A of the work and B does 1/B of the work. In a day, working together they do 1/7 of the work, so:
1/A + 1/B = 1/7
Also: B = 2A (he takes twice as long as A). Substitute in for B:
1/A + 1/(2A) = 1/7
Get a common denominator of 2A:
2/2A + 1/2A = 1/7
Add:
3/2A = 1/7
Cross multiply:
2A = 21
Divide both sides by 2:
A = 10½ days working alone
Note: don't forget to double check your answer. It should take longer for A working alone compared to working together. If you get a smaller answer, you've made a mistake... (like I did the first time I tried this.)
2006-10-13 05:30:20
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answer #1
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answered by Puzzling 7
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First you need to define some parameters to solve the problem.
Let's call the amount of work 'units'. Let's make the total number of 'units' to complete a multiple of 7 to make the math easier. I chose 42. Thus, if there are 42 units to complete in 7 days, that means the rate that A&B worked together is 6 units/day.
Since together they completed 6 units/day and A is twice as efficient as B, that means that A complete 4 units/day and B completed 2 units/day.
Now you can solve the problem for A alone.
Completed units = rate*time
42 units = (4 units/day)*time,
Therefore, the time it takes for A to complete the project is 10.5 days
Hope this helps
2006-10-13 12:32:21
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answer #2
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answered by JSAM 5
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You have to use rates. A + B = (1 job) / (7 days), or 1/7 job/day. At the same time, A = 2B, because A works at twice the rate of B. You can therefore write A + B = 2B + B = 3B = 1/7, so B = 1/21 job/day. A = 2B = 2/21 job/day, and so A requires 21 days to complete the job twice over, or 10.5 days to complete the individual job.
2006-10-13 12:27:47
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answer #3
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answered by DavidK93 7
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A&B can complete the work in 7days
Now A can be regarded as =2B
3B can do in 7days
B alone can do in 21 days
2B can do in 10.5 days
or A can do the work in 10.5 days
2006-10-13 13:18:59
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answer #4
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answered by openpsychy 6
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A=2B
A+B=1/7 days^1
3B=1/7
B=1/21
A=2B=2/21 so
B working alone can do the job in 21/2=10.5 days
2006-10-16 20:00:56
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answer #5
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answered by yupchagee 7
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assuming the number of days for A to complete work = x; B = y;
1st sentence: x = 2y-------(1)
2nd sentence: x + y = 7---(2)
(1) -> (2)
3y = 7
y= 7/3
From (1);
2*(7/3) = x
Thus, x = 14/3 = 4 and 2/3
2006-10-13 12:33:45
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answer #6
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answered by the DoEr 3
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rate * time = quantity of work
A = 2B
B = A/2
(A + B ) * 7 = 1
(A + A/2) * 7 = 1
1.5 * 7 * A = 1
A = 1/10.5
A * T = 1
T / 10.5 = 1
T = 10.5 Will take A 10.5 days
2006-10-13 12:28:33
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answer #7
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answered by Grant d 4
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