Chem help? plz show work?

Question

A mixture of Ne and Ar gases at 351 K contains twice as many moles of Ne as of Ar and has a total mass of 47.0 g. If the density of the mixture is 4.17 g/L, what is the partial pressure (in atm) of Ne?

Answer 1

OK, you have the mass and the density, therefore you can get the volume. 47/(4.17) = 11.27 l
solve for n,
x = moles of Ar, then
2x(atomic mass or Ne) + 1x(atomic mass or Ar) = 47.0 g
use PV=nRT & solve for P,
P=nRT/V
once you have the total pressure, then the partial pressures are,
2/3 P for Ne, and 1/3 P of Ar.

Plug in the values and you have it.

Answer 2

As I said.........................