Well, useless as it might seem, today is 13/10/2006. If you add the individual figures of 1+3+1+2+6=13! Now how spooky is that! The 13th day of this month when added as individual figures also comes to 13! So,when did this last happen and when will it occur again?
2006-10-13 04:10:30 · 11 answers · asked by Anonymous in News & Events ➔ Current Events
well tomorrow it will happen again, and the day after that, and the day after that! think about it! it's adding one more number, and the day is going up by one until it gets to october 20th then it will be off. it's not that hard!
2006-10-13 04:18:45 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Well it will happen when the month and year digits next add up to 9. Next year (2007) already adds up to 9 so that won't work, and you have to wait until 2010 before you get 13/06/2010. The last time it happened was earlier this year, on 13/01/2006.
2006-10-13 11:20:42 · answer #2 · answered by nickers 2 · 0⤊ 0⤋
Take it you are a civil servant trying to kill some time before heading to the pub.
Try this one, 12+38-14x57-119 x66+13-4x29-675+18-5=?
Hey, put the calculator away!!
2006-10-17 08:11:59 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Hello,
I built myself my own chicken coop following the plans I bought on this site http://www.goobypls.com/r/rd.asp?gid=421
Cheers ;)
2014-08-08 09:10:44 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I don't know. But what a sad life you lead. Ha Ha!
2006-10-13 11:14:13 · answer #5 · answered by little weed 6 · 0⤊ 0⤋
no idea if or when it will happen again.
tho nothin bad happened so blah, i dont really care lol
Mj
2006-10-14 03:19:16 · answer #6 · answered by mj_junkie86 3 · 0⤊ 0⤋
Do you also count number plates on cars? UK
2006-10-13 11:20:36 · answer #7 · answered by Anonymous · 0⤊ 0⤋
hey that's really cool! 2010 maybe?
2006-10-13 11:43:56 · answer #8 · answered by imix3 2 · 0⤊ 0⤋
I take to you're into numerology.
2006-10-13 11:22:16 · answer #9 · answered by Anonymous · 0⤊ 0⤋
I just don't care ok.
2006-10-13 11:16:30 · answer #10 · answered by ? 6 · 0⤊ 0⤋