calculate the pH of an aqueous solution of HF at a concenteration of 1.0 M,1.0mM and 1.0 micro mol.(pKa=3.17)?

Answer 1

Find the pH of a 0.2 mol L-1 (0.2M) solution of H2SO4
Write the balanced equation for the dissociation of the acid
HF -----> H+(aq) + F-(aq)
Use the equation to find the [H+]:
1.0 mol L-1 HF produces 1 x 1.0 = 1.0 mol L-1 H+ since HF is a strong acid that fully dissociates
Calculate pH: pH = -log10[H+]
pH = -log10[1.0] = 1.0