does anynoe have any ideas on how much pressure a hydraulic system would take to elevate an average sized car?

Question

im doing this thing for a science project. the thing goes like this: you put your car on a polatform and it gets elevated using a hydraulic system. i wanna know what kind of pressure it would need and what could be the approx. cost of installing this sorta system...

Answer 1

Off hand I do not have an idea. However I will make an attempt to calculate it for you. Average sized car weighs any where between 800 kg to 1200 kg. The normal size of the hydraulic cylinder is around 6inch dia or 150mm dia.
Let us assume that the piston carrying the load is 150mm dia.
Then max pre=1200/.785*150^2= .06794 kg/mm^2
min pressure=800/.785*150^2=.04529kg/mm^2
These pressures are very small of the order of 10lbs/in^2
This pressure will be acting in the cylinder. We have to choose the wall thickness of the cylinder wall to ensure that the hoop tension and bursting pressures are well with in 6ton/in^2 with adequate safety margins. You will have to cost the system. You will need the cylinder piston cobination besides a power pack to operate hydraulic system and various pielines valves and other elements in the system.

Answer 2

You could do it with 1psi if you had a really large and light piston. Or, do it with a tiny piston if you had 5,000psi.One of those big single cylinder lifts with a 10" ram would need about 40 psi. Some of them have about 4" rams inside the big column, and take around 400psi.

Answer 3

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Answer 4

The larger the piston, the lower the pressure needs to be. I'd imagine a happy medium between piston size and hose and pump pressure ratings.would need to be found.