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2006-10-12 22:27:41 · 3 answers · asked by jet 1 in Science & Mathematics Chemistry

3 answers

(m)

Helium Energy Levels
The helium ground state consists of two identical 1s electrons. The energy required to remove one of them is the highest ionization energy of any atom in the periodic table: 24.6 electron volts. The energy required to remove the second electron is 54.4 eV, as would be expected by modeling it after the hydrogen energy levels. The He+ ion is just like a hydrogen atom with two units of charge in the nucleus. Since the hydrogenic energy levels depend upon the square of the nuclear charge, the energy of the remaining helium electron should be just 4x(-13.6 eV) = -54.4 eV as observed.

The fact that the second electron is less tightly bound can be interpreted as a shielding effect; the other electron partly shields the second electron from the full charge of the nucleus. I

Another way to view the energy is to say that the repulsion of the electrons contributes a positive potential energy which partially offsets the negative potential energy contributed by the attractive electric force of the nuclear charge. The description of any electron in a multi-electron atom must find a way to characterize the effect of the other electrons on the energy.

2006-10-12 22:41:40 · answer #1 · answered by mallimalar_2000 7 · 2 0

This site will show you the helium energy levels

2006-10-13 05:39:00 · answer #2 · answered by iamwhoiam 5 · 0 0

check the link this might help u

http://en.wikipedia.org/wiki/Helium

2006-10-13 05:39:28 · answer #3 · answered by rohingrewal 4 · 0 0

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