Just one more because I am still trying?

Question

Factor completely

-3t^3 + r^2-6r

so whats the difference?
Factor each polynomial completely

2x ^2 – x – 10

10a^2 + ab –2b^2

Answer 1

2x^2-x-10
2x^2+4x-5x-10
2x(x+2)-5(x+2)
(x+2)(2x-5)

10a^2+ab-2b^2
10a^2+5ab-4ab-2b^2
5a(2a+b)-2b(2a+b)
(2a+b)(5a-2b)

Answer 2

-3r^3+r^2-6r? Maybe you mean -3r^3+r^2-6r. If so, factor out -r first, as follows: -r(3r^2+r-6). Then find the factors of (3r^2+r-6). But sorry, I can't solve this. Maybe somebody else can. So my answer remains as
-r(3r^2+r-6).

The other two polynomials look simple. The factors are as follows:

2x^2-x-10= (2x-5)(x+2)

10a^2+ab-2b^2=(5a-2b)(2a+b)

Answer 3

-3*t*t*t +r*(r-6)
or
ler r = (6+/-sqrt(36+12t^3))/2 = 3+/-sqrt(9+3t^3)
then
r^2-6r-3t^3 = (r-3-sqrt(9+3t^3))(r-3+sqrt(9+3t^3))

2*-10 = -20, 2 - 10 = -8
4*-5=-20, 2*2 - 5= -1
2*2 - 5*1 = -1, 2*1=2, -5*2 = -10


10*-2 = -20,
5*-4 = -20, 5 - 2*2 = 1
1*5*2*-2 = -20, 5*2=10, 1*-2 = -2

Answer 4

1. 2x^2 - x - 10
= 2x^ +4x - 5x - 10
= 2x(x + 2) - 5(x +2)
= (2x - 5) (x + 2)

2. 10a^2 + ab - 2b^2
= 10a^2 + 5ab - 4ab - 2b^2
= 5a(2a + b) - 2b(2a + b)
= (5a - 2b)(2a + b)