Can someone help me on factoring again?

Question

Here are two more problems #1)3x^y^-xy^-4y^ #2)2x^+3xy+y^ {THE "^" Stand for squared}. It would be great if you can explain how to factor the y, I always get stuck there. Thanks!

Answer 1

1) 3x^2y^2 -xy^2 - 4y^2 i write x^2 as x square
= y^21(3x^2-x-4) taking y^2 common and out
= y^2(3x^2+3x - 4x -4)
= y^2(3x(x+1)-4(x+1) = y^(x+1)*(3x-4)

2)
2x^2 + 3xy + y^2
= 2x^2 + 2xy + xy + y^2
= 2x(x+y) + y(x+y) = (x+y)(2x+y)

Answer 2

have you used the
First
Outer
Inner
Last

Method??


your equations would read:
#1) (3xy-4y)(xy+y)
*hint just do the first then the last and change them accordingly to make your middle.

* then you could also factor out the y^ and then factor the other one like you would normally do
#1) (y^) (3x^-x-4)



#2)you just have to work with this one

(2x+y) (x+y)


hope this helps :)

Answer 3

Okay. The x and y are both variables. In the first problem, there is a y^ in each term. So, take it out just like you would a common factor of a numerical constant. This gives us:
y^(3x^-x-4) Now, you can just solve the remaining as a normal trinomial with one variable.
y^(3x-4)(x+1).

For the second equation, nothing is common to every term. So, let's isolate the x part in the first two terms and treat everything else as a constant. I'd suggest rewriting it as:
2x^+3yx+y^. Now, factor the trinomial thinking of x as the variable.
(2x+y)(x+y).

Answer 4

Hi Dear Raider ;

Part 1
3x ² y ² - xy ² - 4y ²
{ Factor ' y ² ' }
y ² ( 3x ² - x - 4 )
{ you have to factor ' x ' as well . But How ? let ' -x = 3x - 4x ' }
y ² ( 3x ² +3x - 4x - 4 )
{ In this part " 3x ² +3x " Factor " 3x " & In this part "- 4x - 4" Factor " -4 " }
So we have ;
y ² ( 3x ( x +1) - 4 ( x +1) )
{ Factor " x + 1 " }
y ² ( x+1) ( 3x - 4 )

Part 2
2x ² + 3xy + y
{ let 3xy = 2xy + xy }
2x ² + 2xy + xy + y
{ Factor " 2x " in ths part " 2x ² + 2xy " and Factor " y " in this part " xy + y " }
2x (x+y) + y (x+y)
{ Now Factor " x + y ) }
(x + y ) ( 2x + y)

Good Luck

Answer 5

First, in the future, please use ^2 for squared, it's what most people are used to.

1) Factor out a y^2, and you get y^2(3x^2-x-4).
To factor 3x^2-x-4, look for a factorization of the form
(3x+a)(x+b) where a+3b=-1 and ab=-4. a=-4 and b=1 work.

2) Look for a factorization of the form
(2x+ay)(x+by), where a+2b=3 and ab=1. a=1 and b=1 work.