could u please help me with this question, thanks
An equilateral triangle is a triangle that has three congruent sides.
1. Use the information given in the triangle below to find AB, BC, and AC.
2. Determine if the triangle is equilateral or not based on the lengths of the three sides.
Show your work and support your conclusion.
A (3,6) B (3,6) C (1,1)
2006-10-12 16:40:08 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Well, since A and B are the same point, I vote that ABC is a line segment and not a triangle.
QED
2006-10-12 16:42:32 · answer #1 · answered by Anonymous · 3⤊ 0⤋
Use the distance formula. The distance d between two points (x1,y1) and (x2,y2) is
d = sqrt((x1-x2)^2 + (y1-y2)^2).
I'd like to use this formula on the 3 given points, but two of them are the same, so these points don't even form a triangle, let alone an equilateral triangle.
Otherwise, I'd use this formula to compute the lengths of the 3 sides and see if all of them are the same.
2006-10-12 23:44:36 · answer #2 · answered by James L 5 · 1⤊ 0⤋
I think you have something written wrong, because you can't have 2 vertices on the same point.
Right now you just have a line.
2006-10-13 00:02:19 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
AB=sqrt((by-ay)^2+(bx-ax)^2)-sqrt((6-6)^2+(3-3)^2)=sqrt(3^2)=0
BC=sqrt((cy-by)^2+(cx-bx)^2)=sqrt((1-6)^2+(1-3)^2)=sqrt(25+4)=sqrt(29)=5.39
AC=sqrt((cy-ay)^2+(cx-ax)^2)=sqrt((1-6)^2+(1-3)^2)=sqrt(29)=5.39
A & B are the same point so you don't really have a triangle.
2006-10-16 19:34:35 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
use the distance formula:
d=sqrt((x2-x1)-(y2-y1))
2006-10-12 23:45:04 · answer #5 · answered by soggy_dough_nut 2 · 0⤊ 0⤋