please help! i'm having a hard time solving this physics problem...?

Question

an object of mass m on a string is whirled with increasing speed in a horizontal circle. when the string breakds, the oject has speed v (sub knot) and the cricular path has radius R and is a height h above the ground. neglect air friction.

express in terms of h, v sub knot, and g:
time required for the object to hit the ground after the string breaks
horizontal distance traveled from the time string breaks until it hits the ground
the speed of the object jsut before it hits the ground

then:
determine the tension in the string just before the string breaks

i'm not looking for people to solve it for me, i just need some help to derive the correct equation to solve for the problems... please help!

Answer 1

I don't mean to be bitchy, luv, but it's "v sub nought" - nought being an old word for zero.

OK - For the time to hit the ground, remember that all of the object's velocity is horizontal when the string breaks. This means that its initial vertical speed is 0, so all you have to do is find the time it takes an object to fall a distance h from rest. V0 will not be a part of the solution.

For the horizontal distance: use the time you got in part one, and remember that the initial horizontal speed is v0. If we neglect air resistance, that horizontal speed will not change through the problem, so the horizontal distance will just be vt (v being v nought).

The speed of the object just before it hits the ground: use the t from part 1 to find the vertical speed just before it hits the ground. That'll just be gt. You know the horizontal speed is v0, and that they're perpendicular (horizontal and vertical), so all you need there is the Pythagorean Theorem.

The tension in the string: Well, there'll be two components to the tension: there will be a vertical component equal to the weight of the mass (because the string is what's holding it up). There will be a horizontal component equal to the centripetal force necessary to hold the object in that circle. Take those two forces and (again) use the Pythagorean Theorem to sum them.

Does that help?

Edit: Fixed incredibly stupid typo

Answer 2

weight is the stress of gravity on an merchandise and is defined via : F = G M m /r^2 the place G = newtonian gravitational consistent = 6.sixty seven 10^-11 Nm^2/kg^2 m M are the lots of the item and the planet r is the gap from the midsection of the planet the mass of jupiter is approximately 320 circumstances extra beneficial than the earth, and the radius of jupiter is approximately 11 circumstances extra beneficial than the earth (in case you desire extra useful solutions, look them up on line) for this reason, the load on Jupiter would be 320/11^2 extra beneficial than in the international or approximately 2.6 circumstances extra beneficial than in the international, so the load on Jupiter would be 2.6 x 24,561N