Find the perimeter of a rectangle. x/2x-5 on the top and 8/2x-5 on the right side?

Question

Find the perimeter of a rectangle. These are the dimensions that are given picture a rectangle with x/2x-5 on the top and 8/2x-5 on the right side

Answer 1

i'm not doing the calculations for you but heres how:

2(x/2x-5)+2(8/2x-5)=perimeter

Answer 2

Perimeter of a rectangle = 2(length + breadth)

P = 2[x/(2x - 5) + 8/(2x - 5)]

P = 2 (x + 8)/ (2x - 5)

P = (2x + 8)/ (2x - 5)

P = (2x + 5 + 3)/(2x - 5)

P = (2x + 5)/(2x - 5) + 3/(2x - 5)

Answer 3

opposite factors of a rectangle are parallel and equivalent so: Perimeter = Width + Width + length + length = 2*Width + 2*length all of us understand that the fringe equals with 40 4 and the width of the rectangle with 5. for this reason: 40 4 = 2*5 + 2*length 40 4 = 10 + 2*length 2*length = 34 length = 17. So, your rectangle has dimensions: length = 17inches and Width = 5inches.

Answer 4

x/2x-5 + x/2x-5 + 8/2x-5 + 8/2x-5

first is x over all 2x-5, and 8 is over all of 2x-5

combine like terms and you should end up with
p=(2x+16)/(2x-5)


do you need to solve for x?

Answer 5

P = 2((x+8)/(2x-5) or
P = 2(0.5-5-5+(4/x)),
depending on the meaning of x/2x-5 and 8/2x-5

Answer 6

P = 2(L + W)

L = (x/(2x - 5))
W = (8/(2x - 5))

P = 2((x/(2x - 5)) + (8/(2x - 5)))
P = 2((x + 8)/(2x - 5))
P = (2x + 16)/(2x - 5)

Answer 7

p=2l+2w=2(x/(2x-5))+2(8/(2x-5))=2(x+8)/(2x-5)

without any other data, you can't really get anywhere.

Answer 8

Your symboligy is wrong. The "/" means divide.

Please give an equal sign, if one is needed.

Thanks!

Answer 9

cross multiply and solve for x i think.