During an afternoon of target practice, you fire a Winchester .308 rifle of mass 3.8kg. The bullets have a mass of 9.72g and leave the rifle at a muzzle velocity of 860m/s. If you are sloppy and fire a round when the butt of the rifle is not firmly up against your shoulder, at what spped does the rifle butt smash into your shoulder?
2006-10-12 15:38:53 · 6 answers · asked by bdbush007 3 in Science & Mathematics ➔ Physics
it should be simply proportional with mass and speed. The gun weighs 3.8 kg, and the bullet is 0.00972 kg. So set it up like this:
(0.00972/3.8) = (X / 860m/s)
Solving for X, you get X = (0.00972/3.8) * 860 = 2.1998 m/s
2006-10-12 15:48:12 · answer #1 · answered by what_m_i_doing 2 · 0⤊ 0⤋
You use conservation of momentum, but also need to use the mass of the powder. The powder exits much faster than the bullet. Here is a website with a calulator.
http://www.siskguns.com/SISK%20RIFLES%20-%20Recoil%20Calculation.htm
Using a powder mass of 45 grains, the recoil velocity would be about 3 meters per second.
Ranb
2006-10-15 15:00:15 · answer #2 · answered by ranb40 5 · 0⤊ 0⤋
That's an interesting question!
2016-09-19 06:29:57 · answer #3 · answered by ? 2 · 0⤊ 0⤋
Use conservation of momentum
2006-10-12 15:46:18 · answer #4 · answered by arbiter007 6 · 0⤊ 0⤋
This is a good question
2016-08-08 17:04:27 · answer #5 · answered by Anonymous · 0⤊ 0⤋
thanks to each and everyone of you for the replies.
2016-08-23 08:41:52 · answer #6 · answered by ? 3 · 0⤊ 0⤋