Not the tangent law you would see in a right angle triange (opp/ajacent). but a tangent law like the sin law or cosine law.
2006-10-12 15:27:52 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The Law of Tangents was first stated around 1580 by François Viète (Viette, or Vieta). It has always been the least popular of the three, and it's not always found in textbooks... It may be proved by expressing the ratio (a - b)/(a + b) in terms of sin a and sin b, using the Law of Sines. The result is then immediately obtained from the following identity for the denominator and from its counterpart for the numerator (replace b by -b).
The Law of Tangents : (a-b)/(a+b) = tg (a/2 - b/2)/ tg (a/2 + b/2)
Guido
2006-10-12 15:36:37 · answer #1 · answered by Anonymous · 2⤊ 0⤋
Law Of Tangent
2016-11-12 01:11:40 · answer #2 · answered by ? 4 · 0⤊ 0⤋
You can make one if you want.
tan(C) = (1/a) sin(A) 2ab / ( a^2 + b^2 - c^2 )
tan(C) = (1/b) sin(B) 2ab / ( a^2 + b^2 - c^2 )
(The guy who answered right before I did has the better tangent law. This one I've shown you is mostly a joke combination of the sine law and the cosine law. You don't need it.)
2006-10-12 15:42:50 · answer #3 · answered by David S 5 · 2⤊ 0⤋
Since the sine law and cosine law cover all types of triangles, a tangent law is not needed.
2006-10-12 15:33:38 · answer #4 · answered by hayharbr 7 · 0⤊ 1⤋
Yes there is one. With usual notation of trigonometry[a is side opp to angle A ...] It states,
tan[ (B-C)/2]= [(b-c)/(b+c)]cot(A/2)
2006-10-12 15:41:00 · answer #5 · answered by bskelkar 7 · 2⤊ 0⤋
Remember cheif SOHCAHTOA
sine=opposity/hypotenuse
cosine=adjacent/hypotenuse
tangent=opposite/adjecent
2006-10-16 12:23:37 · answer #6 · answered by yupchagee 7 · 1⤊ 2⤋
there's a sin law and cosine law..but not a tangent law...
2006-10-12 15:37:42 · answer #7 · answered by alex d 1 · 0⤊ 4⤋
what should it state ?
2006-10-12 15:37:39 · answer #8 · answered by gjmb1960 7 · 0⤊ 2⤋