Mathmatics: A square lot was widened by 3 meters on one side and by 5 meters on another, it lost 185 meters?

Question

square. What was the original size of the lot? Let X= the length of 1 original side

Sorry, I meant to say the street was widened on each side , by 3 meters and 5 meters

Answer 1

You can't lose area when you add length to a side. I'll assume you meant that it now has 185 more meters squared in the area.

Assuming that opposite sides were both extended, we have (X+3)(X+5)=X^2+185.

X^2+8X+15=X^2+185
8X=160
X=20

So the original side length was 20 meters.

If both sides were not extended, then the problem becomes harder to find the equation for, but it's just triangles on the ends of a square.

185+X^2=X^2+5X/2+3X/2
185=4X
X=46.25

I think the first result is more likely. Assuming what I did of course.

Answer 2

If a man or woman describes a parent as being '5 metres sq.' it skill that that the parent is a sq. with sides 5 metres long, the part of that's 25 squarem If the define of the parent is '5 sq. metres' all you comprehend is the part of the parent. the form and lengths of the perimeters are no longer time-honored i.e. a rectangle 2.5m x 2m is a 5sq.m parent yet a circle of diameter 2.523m is likewise a 5sq.m parent. So there's a international of distinction meant in the two expressions.

Answer 3

(x+3)(x-5) = x^2 - 185

x^2 - 2x - 15 = x^2 - 185, x =85... the original side

Answer 4

(x+3)(x+5)=x^2 - 185
x^2 + 8x + 15 = x^2 -185
x^2- x^2 +8x = -185 - 15
8x=-200
x=-25

????

impossible sorry bud

Answer 5

there are endless solutions because it is one equation with 2 unknowns ,to solve an equation the number of unknowns has to equilize the number of equations

Answer 6

Impossible. If you've added length to the sides, the area cannot decrease. Please submit the question again.

Answer 7

I don't get it.