Geniuses Only!!!?

Question

The warden of a state prison offers 3 prisoners a chance of freedom every year on his bday. He takes the 3 prisoners and lines them up in front of a brick wall. The prisoners: A, B, and C are lined up in a way so that C can see B and A....B can only see A...and A can't see anything but the brick wall.
___wall_____
A
B
C
The warden then blindfolds them and puts a hat on each of them and explains to them the rules:
-5 hats in a box...3 red, 2 blue...
-hats are chosen at random and placed randomly on each of their heads
-the prisoners face the wall at all times
-again, C can see B's hat and A's hat....B can see A's hat...A can't see anything
-prisoners cant see their own hat
-If the prisoners can guss wat color hat they are wearing, they are free
-If they guess wrong then +10 more years to their sentence
-If they dont guess, then they serve original sentence

Prisoner C goes first
Prisoner C does not know and chooses not to guess
Prisoner B goes next and does not know also, and does not guess
Prisoner A goes last and knows the color of his hat and guesses right and goes free

wat color was A and how did he know?

this riddle does not have a lame answer like
"theres a mirror in front of A"
this riddle has a real, mathematical solution
if u can do this ur IQ is well over 120

forgot to mention...warden takes off the blindfolds then the prisoners start guessing....(just clearing things up)

to get u guys in the right direction im gonna give u guys a hint
USE CASES
3 blue hats 2 reds
if A and B wore 2 red hats, C would see that and know he was wearing a blue
but C did not know, so A and B cannot both be wearing red hats............(keep going)

Answer 1

I don't think this requires a genius to answer. It is just a simple puzzle and can be solve with logic.

The answer is red.

First, if C sees two blues, he knows he has red, so he must see either two reds, or two combinations of blue and red.

Second, if B sees blue on A, then he knows he is wearing red, because C would have answer already.

Third, A has red because those are the last two combinations that can exist, A with red and B with either red or blue.

Answer 2

NO!!! A AND B CAN BOTH BE WEARING RED HATS, THERE'S THREE.
IF A AND B WERE WEARING RED HATS AND C COULD SEE THAT, IT DOESN'T MEAN C ISN'T WEARING A RED HAT IF THERE ARE 3 RED HATS AVAILABLE. THE ONLY WAY C WOULD KNOW WHAT COLOR HIS OWN HAT WAS IS IF A AND B ARE BOTH WEARING BLUE. C DIDN'T KNOW WHAT COLOR HIS HAT WAS SO A AND B ARE NOT BOTH WEARING BLUE. WHEN C SAID THAT, B FIGURED OUT THAT AT LEAST EITHER HE OR A HAD A RED HAT ON. HE CAN SEE A. IF A HAD A RED HAT ON, B COULD STILL HAVE A BLUE HAT OR A RED HAT AND B WOULDN'T KNOW WHAT COLOR HE HAD. IF A HAD A BLUE HAT ON HE STILL WOULDN'T KNOW WHAT COLOR HE HAD. THEN WE COME TO A-WE LEARNED FROM C THAT EITHER HE OR B HAD A RED HAT, AT LEAST ONE OF THEM, MAYBE BOTH, THERE WERE 3 RED HATS. WE LEARNED NOTHING FROM B. HE COULD SEE A. A COULD HAVE BLUE OR RED, OR HE COULD HAVE BLUE OR RED AND THERE ARE STILL ENOUGH HATS LEFT. I SAY, THERE IS NO SOLUTION.

okay, let me think about this and try to explain it. C doesn't know, which means, A and B both have red or they have one of each, red and blue. we come to B, who can see A. if A had blue, B would automatically know he, himself had red cuz C didn't know. (A and B could not both have blue cuz C would have known he, himself had red but he didn't know) but...B didn't know what color he had and the only way he couldn't have known is if A had a red hat, leaving other possibilities for his own hat. so, when B said he didn't know, A could be sure his own hat was red. RED. red is the answer.

Answer 3

C must have seen one hat of each color or two red, otherwise he would have known his.

Then B looks and knowing that the options are either one of each or two red he would guess if he saw blue but since he sees red he does not know therefore he passes

A narrows the options same as just outlined and determines he must be wearing a red hat.

Answer 4

the answer is red, because if C could see B and A's color but still did not know his color then B and A must be wearing red hats and therefore C's could either be red or blue, B hearing that C could not guess despite being able to see B and A's hat has no clue as it could be either, A concludes that he is wearing red

but don't tease me, i'm no genius.

Answer 5

Um...if the prisoners are blindfolded, how do they see the hats?
(Also, how can the warden put a hat on them, explain the rules, and then pull out another hat to put on?)

Answer 6

well, C can see A and B becasue he is the tallest. A knows what hat he has on because he has 180 degree eyesight and B & C have on blue hats on, so A's hat has to be red.

Answer 7

even imitation geniuses wouldn't waste time with this silliness