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how can i factor this? can someone please explain it to me in mathematical words so i can understand it mathematically for the test.... here is the question how can i factor (a+1) squared subtract (b-3) squared? please explain in mathematical details in words!!! tyvm!!!

2006-10-12 14:34:07 · 8 answers · asked by Anonymous in Education & Reference Homework Help

people ya ty great answers ^.^ but um.. its grade 10 factoring o.o; FACTORING not expanding

2006-10-12 14:48:16 · update #1

8 answers

Try multiplying everything out, then combining:

(a+1)^2 - (b-3)^2 =

(a+1)(a+1) - (b-3)(b-3) =

a^2 + 2a + 1 - (b^2 - 6b + 9) =

a^2 + 2a + 1 - b^2 + 6b - 9 =

a^2 + 2a - b^2 + 6b - 8

Not sure you can go much further with it than that.

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EDITED TO ADD: Answerers #3 (Steiner) and #6 (P.Rutherford) have it! Answerer #3 gave the hint, Answerer #6 did the work. If you want full credit on this homework problem, go with Answerer #6.

2006-10-12 14:38:14 · answer #1 · answered by I ♥ AUG 6 · 0 0

Okay (a+1)^2 - (b-3)^2 factored:

Let x = (a+1) and y = (b-3), so we have:

x^2^- y^2 factoring this is simple:

(x+y)(x-y) now get the original variables back:

[(a+1) + (b-3)][(a+1) - (b-3)] simplify

[a + b -2][a - b +4] Voila!

2006-10-12 21:44:15 · answer #2 · answered by p_rutherford2003 5 · 1 0

first, since both the terms are squares you can find the square root of the problem. (hint: the square root of a number squared is the number itself) so then you should have (a+1) - (b-3). then since in both parenthesis is just addition and subtraction you can ignore them so you would get a-b+4, because positive 1 minus negitive 3 = 4

hope this helped

2006-10-12 23:07:07 · answer #3 · answered by princess 2 · 0 1

Hint: You have 2 squares. How do you factor their difference?

2006-10-12 21:37:55 · answer #4 · answered by steiner1745 7 · 1 0

This might help, use FOIL.

First, Outside, Inside, Last.

(a+1)(a+1)

(a*a)+(a*1)+(1*a)+(1+1)
F O I L

Hope that helps.

2006-10-12 21:37:01 · answer #5 · answered by frozenpancake582 4 · 0 0

I am not competley sure but I have an idea.
(a + 1)^2 - (b - 3)^2
change signs
a + 1^2 + -b + -3^2
a+1 + -b + 9
a+10 +-b

2006-10-12 21:40:38 · answer #6 · answered by ^..^ 4 · 0 1

If you mean (a+1)^2 - (b-3)^2 then:

(a+1)(a+1)=a^2 + 2ab + b^2

(b-3)(b-3)=b^2 - 6b +9

(a^2 + 2ab +b^2) - (b^2 - 6b +9)

= a^2 + 2ab +b^2 - b^2 + 6b -9

=a^2 + 2ab +6b -9

2006-10-12 21:46:33 · answer #7 · answered by fathotra 1 · 0 1

srry. I'm not good at math.

2006-10-12 21:36:13 · answer #8 · answered by ruty 1 · 0 2

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