Math : Find three consecutive even integers such that the sum of the smallest and largest is 36.
I will give out best answer
2006-10-12 14:30:13 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x, x + 2, x + 4
x + (x + 4) = 36
x + x + 4 = 36
2x + 4 = 36
2x = 32
x = 16
The numbers are 16, 18, and 20
2006-10-12 15:14:31 · answer #1 · answered by Sherman81 6 · 1⤊ 0⤋
16, 18, 20
16+20=36
2006-10-12 14:34:08 · answer #2 · answered by ViCKi!™|` 5 · 1⤊ 0⤋
the consecutive even integers are...... n,n+2 and n+4
n,(n+2),(n+4)
where n + (n+4) = 36
2n + 4 = 36
2n = 36-4
2n = 32
n = 32/2
n = 16
the even integers are 16,18 and 20
smallest no. is 16 and the largest no. is 20
giving you a sum of 36
2006-10-12 15:20:57 · answer #3 · answered by Danny_V 1 · 1⤊ 0⤋
integers are n, n+2 & n+4
n+n+4=36
2n=32
n=16
integers are 16, 18, 2016+20=36
2006-10-12 14:33:39 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
X+X+2=36.
2X=34.
X is 17.
Therefore, your numbers are 17, 18, and 19.
2006-10-12 14:32:40 · answer #5 · answered by zex20913 5 · 0⤊ 3⤋
17,18,19 because 17+19=36
2006-10-12 14:38:06 · answer #6 · answered by Anonymous · 0⤊ 3⤋