Okay...
One root of 3x^3 - 5x^2 - 3x +2 = 0 is 2
Find the other roots...
The answer is 2 and
(-1 + the square root of 13) / (6) and
(-1 - the square root of 13) / (6)
Please explain how you got there as best you can and then best explainer and quickest explainer wins 10 points!!! Thanks!
2006-10-12 14:27:45 · 3 answers · asked by JitterBug589 3 in Education & Reference ➔ Homework Help
Since you know 2 is one factor, you can divide your equation by (x-2) to get a quadratic equation, then use the quadratic formula to determine the roots of the quadratic equation.
(3x^3 - 5x^2 - 3x + 2 ) =
(x - 2) (3x^2 + x - 1)
I assume you know how to apply the quadratic formula to (3x^2+x-1), so I won't do that part. But that's how you get the other two roots (-1+SQRT13)/6 and (-1-SQRT13)/6
2006-10-12 14:30:39 · answer #1 · answered by I ♥ AUG 6 · 1⤊ 0⤋
3 -5 -3 2
0 6 2 -2
by synthetic division
when we divide by x-2 we get
6x^2+2x-2=0
3x^2+x-1=0
use the quadratic formula for the other roots
2006-10-12 21:33:43 · answer #2 · answered by raj 7 · 0⤊ 0⤋
http://online.math.uh.edu/Math1330/Appendix/sA2/index.html
on the left side under topic click on division
2006-10-12 21:30:21 · answer #3 · answered by nothingplaying 2 · 0⤊ 0⤋