Given the function H(x) = x2 - 3x + 5, H(a - b) = ____.
2006-10-12 13:55:22 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
H(a-b) = (a-b)^2 - 3(a-b) + 5 = a^2-2ab+b^2-3a+3b+5.
2006-10-12 13:58:50 · answer #1 · answered by James L 5 · 1⤊ 0⤋
(a-b)^2-3(a-b)+5
2006-10-12 21:00:46 · answer #2 · answered by raj 7 · 0⤊ 0⤋
H(x) = x^2 - 3x + 5
H(a - b) =(a-b)^2-3(a-b)+5=a^2-b^2-3a+3b+5
H(a-b)=a^2-3a-b^2+3b+5
2006-10-12 22:08:34 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
just plug in (a-b) for every x in the equation, it's asking for the function of x, if x is equal to (a-b)
H(a-b)=(a-b)2 - 3(a-b)+ 5
2006-10-12 21:06:33 · answer #4 · answered by ? 2 · 0⤊ 0⤋
h(a - b) = (a - b)^2 - 3(a - b) + 5
h(a - b) = ((a - b)(a - b)) - 3a + 3b + 5
h(a - b) = (a^2 - ab - ab + b^2) - 3a + 3b + 5
h(a - b) = a^2 - 2ab + b^2 - 3a + 3b + 5
2006-10-12 22:35:27 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋