Given f(x) = x2 + 6 and g(x) = 2x - 1, f [g(x)] = ____.
2006-10-12 13:52:37 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
fog=(2x-1)^2+6=4x^2-4x+1+6
=4x^2-4x+7
2006-10-12 13:54:26 · answer #1 · answered by raj 7 · 0⤊ 0⤋
I agree.
fog = f(g(x)) = (2x-1)^2 + 6
= 4x^2 - 4x +1 + 6
= 4x^2 - 4x +7
2006-10-12 14:00:36 · answer #2 · answered by naike_10021980 2 · 0⤊ 0⤋
I'll assume you mean
f(x) = x^2 + 6
and given,
g(x) = 2x -1
find f[g(x)]
substitute the 2x-1 into the f(x) equation, and you get
f[g(x)] = (2x -1)^2 + 6
and then you simplify the right side, and you're done.
(2x-1)^2 = 4x^2 - 4x + 1
so plug that into f[g(x)]
f[g(x)] = 4x^2 - 4x + 1 + 6
f[g(x)] = 4x^2 - 4x + 7
2006-10-12 13:59:58 · answer #3 · answered by Glenn 2 · 0⤊ 0⤋
is that x^2 or 2x
2006-10-12 13:54:11 · answer #4 · answered by travislizzie 2 · 0⤊ 0⤋
f(x) = x^2 + 6
g(x) = 2x - 1
f(g(x)) = f(2x - 1)
f(2x - 1) = (2x - 1)^2 + 6
f(2x - 1) = ((2x - 1)(2x - 1)) + 6
f(2x - 1) = (4x^2 - 2x - 2x + 1) + 6
f(2x - 1) = 4x^2 - 4x + 1 + 6
f(2x - 1) = 4x^2 - 4x + 7
so
f(g(x)) = 4x^2 - 4x + 7
2006-10-12 15:36:48 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
whenever you spot such kind of situation concerning tan or cot or cosec or sec ,convert all of them to sin and cos cos x+a million/sinx+sinx/cosx take l.c.m. in denominator so denominator will become(sin x * cosx +sinx)/cosx take sinx basic it becomessinx(cosx +a million) cancel cos x +a million from numerator and denominator so it incredibly is going to become a million/sinx/cos x =cot x
2016-12-13 07:16:32 · answer #6 · answered by Anonymous · 0⤊ 0⤋