Given J = 2x + 6, J-1 =
2006-10-12 13:40:59 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
subtract 1 from both sides of the original equation...
J-1=2x+5
2006-10-12 13:43:14 · answer #1 · answered by Your Best Fiend 6 · 0⤊ 0⤋
J=2x + 6
J - 1
=2x + 6 - 1
=2 x + 5
2006-10-12 13:43:45 · answer #2 · answered by danjlil_43515 4 · 0⤊ 0⤋
J = 2x + 6
J-1 =2x+6-1=2x+5
2006-10-12 15:10:54 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
(2x + 6) - 1
= 2x + 5
2006-10-12 13:45:11 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2x+5
2006-10-12 13:49:18 · answer #5 · answered by raj 7 · 0⤊ 0⤋
J..... = 2x + 6
....-1 =...........-1
J - 1 = 2x + 6 - 1
2006-10-12 13:46:18 · answer #6 · answered by Helmut 7 · 0⤊ 0⤋
are you asking
inverse of J, or j^-1
if so, then
J = 2x + 6
x = 2J^(-1) + 6
x - 6 = 2J^(-1)
J^(-1) = (1/2)x - 3
ANS :
J^-1 = (1/2)x - 3
2006-10-12 15:39:46 · answer #7 · answered by Sherman81 6 · 0⤊ 0⤋